Calculate the depth of water in a pool where the water pressure is 25000 Pa. The density of water is 1000kg/m cubic and the gravitational field strength on earth is 10N/kg

To calculate the depth of water in a pool given the water pressure, we can use the following formula for pressure in a fluid:

\[
P = \rho \cdot g \cdot h
\]

Where:
- \( P \) is the pressure (25,000 Pa),
- \( \rho \) is the density of water (1,000 kg/m³),
- \( g \) is the gravitational field strength (10 N/kg),
- \( h \) is the depth of water (unknown).

Rearranging the formula to solve for \( h \) (depth):

\[
h = \frac{P}{\rho \cdot g}
\]

Now, substitute the values:

\[
h = \frac{25000 \, \text{Pa}}{1000 \, \text{kg/m}^3 \times 10 \, \text{N/kg}}
\]

\[
h = \frac{25000}{10000} = 2.5 \, \text{m}
\]

So, the depth of the water is **2.5 meters**.

Would you like any further explanation or details on this solution?

Here are 5 related questions:
1. How does water pressure change with depth?
2. What is the effect of gravity on fluid pressure?
3. How would the depth change if the pressure increased to 50,000 Pa?
4. What if the pool was filled with a fluid denser than water?
5. How does atmospheric pressure affect calculations at great depths?

**Tip:** Water pressure increases linearly with depth, so doubling the depth would double the pressure.

Calculate the depth of water in a pool where the water pressure is 25000 Pa. The density of water is 1000kg/m³ and the gravitational field strength on Earth is 10N/kg.

Learn how to calculate the depth of water in a pool when the water pressure is 25,000 Pa, the density of water is 1000 kg/m³, and gravitational field strength is 10 N/kg. This solution covers fluid mechanics and uses key formulas such as P = ρ ⋅ g ⋅ h.

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