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This problem asks for the depth \( h \) based on hydrostatic pressure.

The hydrostatic pressure formula is:

\[
P_h = \rho \cdot g \cdot h
\]

Where:
- \( P_h = 276000 \, \text{Pa} \) (given),
- \( \rho = 920 \, \frac{\text{kg}}{\text{m}^3} \) (density),
- \( g = 10 \, \frac{\text{N}}{\text{kg}} \) (gravitational acceleration),
- \( h \) is the depth, which we need to find.

Rearranging the formula to solve for \( h \):

\[
h = \frac{P_h}{\rho \cdot g}
\]

Now, substituting the given values:

\[
h = \frac{276000}{920 \cdot 10} = \frac{276000}{9200} = 30 \, \text{m}
\]

Since the result should be in decimeters (dm), and 1 m = 10 dm, we convert it:

\[
h = 30 \times 10 = 300 \, \text{dm}
\]

Thus, the depth \( h \) is **300 dm**.

Would you like further details or have any questions?

Here are some related questions:
1. How would the calculation change if the density of the liquid increased?
2. Why is gravitational acceleration important in hydrostatic pressure calculations?
3. What would happen to \( h \) if the hydrostatic pressure were halved?
4. How would you convert \( h \) to centimeters (cm)?
5. How does atmospheric pressure impact hydrostatic pressure in open containers?

**Tip:** When solving physics problems, always ensure the units match, and convert them appropriately before final calculations.

Calculate the depth h based on hydrostatic pressure (Ph = 276000 Pa, ρ = 920 kg/m³, g = 10 N/kg). Round the result to one decimal place in decimeters.

Find the depth h using the hydrostatic pressure formula with Ph = 276000 Pa, ρ = 920 kg/m³, and g = 10 N/kg. This solution explains unit conversion to decimeters (dm) and step-by-step calculations. Suitable for Grades 10-12 physics students.

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