In an election constituted by two parties, party A secured 15% of total votes more than party B. If party B got 93500 votes and there are no invalid votes. By how many votes did B lose the election? 

Let's solve this step-by-step.

### Step 1: Understanding the problem
Let the total votes secured by Party B be \( x \). We are given that:

1. Party B's votes = 93,500.
2. Party A secured 15% more votes than Party B.

### Step 2: Calculate Party A's votes
If Party B got 93,500 votes, then Party A got:
\[
x + 0.15x = 1.15x
\]
So:
\[
\text{Votes secured by Party A} = 1.15 \times 93,500
\]
\[
= 1.15 \times 93,500 = 107,525
\]

### Step 3: Determine the vote difference
The difference in votes between Party A and Party B is:
\[
107,525 - 93,500 = 14,025
\]

Therefore, Party B lost the election by **14,025 votes**.

Would you like more details or have any questions?

### Follow-up Questions:
1. What percentage of the total votes did Party A secure?
2. How many total votes were cast in this election?
3. What was the vote percentage difference between the two parties?
4. If Party B had won by 10,000 votes, how many total votes would they have needed?
5. What would be Party A's vote count if Party B had 20% fewer votes?

### Tip:
To find percentage increases, always multiply the original value by \( 1 + \text{(percentage increase)} \).

In an election constituted by two parties, party A secured 15% of total votes more than party B. If party B got 93500 votes and there are no invalid votes. By how many votes did B lose the election?

Learn how to determine the vote difference in a two-party election where Party A secured 15% more votes than Party B. With Party B getting 93,500 votes, find out how many votes Party B lost the election by. This problem covers percentage calculations and basic arithmetic, suitable for students in Grades 6-8.

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