It looks like you've shared an image with pyramids and a table to calculate the volume of square-based pyramids. The volume of a pyramid can be calculated using the formula:

$V = \frac{1}{3} \times \text{Base Area} \times \text{Height}$

For a square base pyramid, the base area is:

$\text{Base Area} = \text{side length}^2$

Let me walk through the first example in the image (Pyramid 1), where the side length is 9 cm and the height is 7 cm.

Step-by-step solution:

1. Base Area: $\text{Base Area} = 9^2 = 81 \, \text{cm}^2$

2. Volume: $V = \frac{1}{3} \times 81 \, \text{cm}^2 \times 7 \, \text{cm} = \frac{1}{3} \times 567 \, \text{cm}^3 = 189 \, \text{cm}^3$

So, the volume of the first pyramid is 189 cm³.

Would you like to proceed with solving the others, or do you have any specific questions about the process? Let me know if you'd like me to continue with further examples from the sheet!

Questions you might find helpful:

1. What is the volume of a square-based pyramid if the base side is 5 cm and the height is 10 cm?
2. How does changing the base area affect the volume of the pyramid?
3. What is the relationship between the height and the volume of the pyramid?
4. Can we use this formula for pyramids with triangular or other polygonal bases?
5. How do different units of measurement (e.g., inches vs. centimeters) impact the volume calculation?

Tip:

Always ensure the side of the square base and the height are measured in the same unit before calculating the volume!