Himalayan pink salt has a density of 1.03 g/mL. 

Calculate the volume, in liters (L), per kg of that salt. Include units.



We are given:

- The density of Himalayan pink salt: \( 1.03 \, \text{g/mL} \)
- The mass of the salt: \( 1 \, \text{kg} \) (which is \( 1000 \, \text{g} \))

We need to find the volume in liters (L) per kilogram (kg) of salt.

### Step 1: Use the formula for density.
The formula for density \( \rho \) is:
\[
\rho = \frac{m}{V}
\]
where \( \rho \) is the density, \( m \) is the mass, and \( V \) is the volume.

Rearranging the formula to solve for volume \( V \):
\[
V = \frac{m}{\rho}
\]

### Step 2: Convert the mass into grams.
Since we are given \( 1 \, \text{kg} = 1000 \, \text{g} \), we can now calculate the volume in mL:
\[
V = \frac{1000 \, \text{g}}{1.03 \, \text{g/mL}} \approx 970.87 \, \text{mL}
\]

### Step 3: Convert milliliters to liters.
We know that \( 1000 \, \text{mL} = 1 \, \text{L} \), so:
\[
V = \frac{970.87 \, \text{mL}}{1000} \approx 0.9709 \, \text{L}
\]

### Final Answer:
The volume of Himalayan pink salt per kilogram is approximately \( 0.9709 \, \text{L} \).

Let me know if you would like more details or have any questions! Here are some related questions:

1. How would the volume change if the salt’s density were lower?
2. What is the significance of density in materials science?
3. How can density affect the use of Himalayan pink salt in cooking?
4. How would you find the mass if given volume and density?
5. What is the volume of 500 g of this salt?

**Tip**: Always make sure to convert all units to the same system when using formulas!

Himalayan pink salt has a density of 1.03 g/mL. Calculate the volume, in liters (L), per kg of that salt. Include units.

Learn how to calculate the volume of Himalayan pink salt given its density of 1.03 g/mL. This step-by-step solution covers density concepts, unit conversions, and volume calculations. Ideal for Grades 9-10.

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