Ethylene glycol, commonly used as automobile antifreeze, has a density of 1.1088 g/ml at room temperature. What is the volume (L) of 1.00 kg of ethylene glycol?

To find the volume of ethylene glycol, we can use the relationship between mass, density, and volume:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

This can be rearranged to solve for volume:

\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]

### Given:
- **Mass** \( m = 1.00 \, \text{kg} = 1000 \, \text{g} \)
- **Density** \( \rho = 1.1088 \, \text{g/mL} \)

### Calculation:

\[
\text{Volume} = \frac{1000 \, \text{g}}{1.1088 \, \text{g/mL}} \approx 902.79 \, \text{mL}
\]

Since 1 liter (L) = 1000 mL:

\[
\text{Volume} = \frac{902.79 \, \text{mL}}{1000} \approx 0.9028 \, \text{L}
\]

### Final Answer:
The volume of 1.00 kg of ethylene glycol is approximately **0.9028 liters**.

Would you like more details or have any questions?

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Here are 5 related questions:
1. How would the volume change if the temperature of ethylene glycol increased?
2. What is the significance of density in determining the quality of antifreeze?
3. How does the density of ethylene glycol compare to that of water?
4. How can you calculate the mass if only the volume and density are given?
5. What are other common uses of ethylene glycol besides antifreeze?

**Tip:** When working with unit conversions, especially in chemistry, always keep track of your units throughout the calculation to ensure accuracy.

Learn how to calculate the volume of ethylene glycol when given its mass and density. This problem involves using the density formula to find volume, including unit conversions from grams to liters. Suitable for advanced high school students and chemistry enthusiasts.

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