What is the mass in grams of 367  mL
  of ethylene glycol?        
Express your answer in grams to three significant figures.
 


To find the mass of ethylene glycol, we can use the formula:

\[
\text{Mass} = \text{Density} \times \text{Volume}
\]

### Given:
- Volume (\( V \)) = 367 mL
- The density of ethylene glycol (\( \rho \)) = 1.11 g/mL (standard value for ethylene glycol)

Now, applying the formula:

\[
\text{Mass} = 1.11 \, \text{g/mL} \times 367 \, \text{mL}
\]

\[
\text{Mass} = 407.37 \, \text{g}
\]

To three significant figures, the mass is:

\[
\boxed{407 \, \text{g}}
\]

Let me know if you'd like more details on this calculation or have any other questions!

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Here are 5 related questions:
1. How do you convert mL to liters and why is it important?
2. What is the significance of using significant figures in scientific calculations?
3. How would the mass change if the density of ethylene glycol was higher?
4. How do temperature variations affect the density of liquids like ethylene glycol?
5. What are some practical applications of ethylene glycol in everyday life?

**Tip:** Always double-check the units when working with physical quantities in formulas!

What is the mass in grams of 367 mL of ethylene glycol? Express your answer in grams to three significant figures.

Find the mass of ethylene glycol when given a volume of 367 mL and using the standard density of 1.11 g/mL. This step-by-step solution explains how to apply the formula Mass = Density × Volume and rounds the answer to three significant figures. Suitable for high school students.

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