Math Problem Statement

A piece of paper cut from an 8-inch circle and shaped like the following sector is cut out and rolled up to give a circular cone shape. What is the volume of the cone? (Use decimal notation. Give your answer to one decimal place.)

Solution

To find the volume of the cone formed when this sector is rolled up, let’s go through the steps carefully.

Step 1: Determine the Radius of the Base of the Cone

The given sector has a radius of 8 inches and a central angle of 80°. When rolled into a cone, the arc length of the sector becomes the circumference of the base of the cone.

  1. Calculate the arc length of the sector:

    Arc length=θ360×2πr\text{Arc length} = \frac{\theta}{360^\circ} \times 2 \pi r where:

    • θ=80\theta = 80^\circ
    • r=8r = 8 inches

    Arc length=80360×2π×8=29×2π×8\text{Arc length} = \frac{80}{360} \times 2 \pi \times 8 = \frac{2}{9} \times 2 \pi \times 8 =16π95.59 inches= \frac{16 \pi}{9} \approx 5.59 \text{ inches}

    So, the circumference of the cone's base is approximately 5.59 inches.

  2. Calculate the radius of the base of the cone:

    Since the circumference CC of the base is given by C=2πRC = 2 \pi R, where RR is the radius of the base of the cone:

    R=C2π=5.592π0.89 inchesR = \frac{C}{2 \pi} = \frac{5.59}{2 \pi} \approx 0.89 \text{ inches}

Step 2: Determine the Slant Height of the Cone

The slant height of the cone is the same as the radius of the original sector, which is 8 inches.

Step 3: Find the Height of the Cone

Using the Pythagorean theorem in the right triangle formed by the height hh, radius RR, and slant height ss (where s=8s = 8 inches):

h=s2R2=820.892h = \sqrt{s^2 - R^2} = \sqrt{8^2 - 0.89^2} h=640.792163.20797.95 inchesh = \sqrt{64 - 0.7921} \approx \sqrt{63.2079} \approx 7.95 \text{ inches}

Step 4: Calculate the Volume of the Cone

The volume VV of a cone is given by:

V=13πR2hV = \frac{1}{3} \pi R^2 h

Substituting R0.89R \approx 0.89 inches and h7.95h \approx 7.95 inches:

V=13π(0.89)2×7.95V = \frac{1}{3} \pi (0.89)^2 \times 7.95 V13π×0.7921×7.95V \approx \frac{1}{3} \pi \times 0.7921 \times 7.95 V13π×6.3V \approx \frac{1}{3} \pi \times 6.3 V6.6 cubic inches (to one decimal place)V \approx 6.6 \text{ cubic inches (to one decimal place)}

Answer:

The volume of the cone is approximately 6.6 cubic inches.

Would you like further details on any step, or have any questions?


Here are five additional questions to expand your understanding:

  1. How would the volume change if the central angle were different, say 120°?
  2. What effect does increasing the radius of the sector have on the cone’s dimensions?
  3. How do we calculate the surface area of this cone after it’s formed?
  4. If the cone is filled with a liquid, how much liquid would it hold in liters?
  5. What are other practical applications of converting sectors into cones?

Tip: Always double-check units when solving geometry problems, as volume and area formulas are sensitive to consistent units.

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Math Problem Analysis

Mathematical Concepts

Geometry
Conic Sections
Volume of Cone
Arc Length

Formulas

Arc length = (θ / 360) * 2πr
Circumference of a circle = 2πR
Volume of a cone = (1/3)πR^2h
Pythagorean theorem: h = √(s^2 - R^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

High School (Grades 9-12)