To find the vertical component of Vector B, we can break down the vector into its horizontal (x) and vertical (y) components using trigonometric functions.

Given:

• Vector B has a magnitude of $70 \, \text{N}$
• The direction is 75 degrees north of east

Vertical Component (along the y-axis):

The vertical component of a vector is given by:

$\text{Vertical Component (B)} = B \cdot \sin(\theta)$

Where:

• $B = 70 \, \text{N}$ (magnitude of Vector B)
• $\theta = 75^\circ$ (angle north of east)

Let's calculate this.

$\text{Vertical Component} = 70 \cdot \sin(75^\circ)$

Now, I'll compute that.The vertical component of Vector B is approximately 67.6 N.

Would you like more details or have any other questions?

Here are 5 related questions to explore:

1. How do you calculate the horizontal component of Vector B?
2. How would you find the vertical component of Vector A?
3. Can you describe how to add vectors analytically?
4. What is the resultant of Vector B and another vector pointing west?
5. How would changing the angle of Vector B affect its vertical component?

Tip: Always use sine for the vertical component and cosine for the horizontal component of a vector when dealing with angles from the horizontal axis.