a particle starts from a point with a velocity of 24m/s and acceleration -2m/s calculate the velocity of the bicycle after 8s

To find the velocity of the particle after 8 seconds, you can use the following kinematic equation:

\[
v = u + at
\]

Where:
- \( v \) is the final velocity.
- \( u \) is the initial velocity, which is \( 24 \, \text{m/s} \).
- \( a \) is the acceleration, which is \( -2 \, \text{m/s}^2 \) (since it's deceleration).
- \( t \) is the time, which is \( 8 \, \text{seconds} \).

Substituting the values:

\[
v = 24 \, \text{m/s} + (-2 \, \text{m/s}^2 \times 8 \, \text{seconds})
\]

\[
v = 24 \, \text{m/s} - 16 \, \text{m/s}
\]

\[
v = 8 \, \text{m/s}
\]

So, the velocity of the particle after 8 seconds is **8 m/s**.

Would you like more details or have any questions?

Here are 5 related questions:

1. What will be the velocity after 12 seconds with the same acceleration?
2. How far will the particle travel in the first 8 seconds?
3. How long will it take for the particle to come to a stop?
4. What would the velocity be if the acceleration was instead positive \(2 \, \text{m/s}^2\)?
5. What is the significance of negative acceleration in real-world scenarios?

**Tip:** Always check the signs (positive or negative) of acceleration to determine if the object is speeding up or slowing down.

Learn how to calculate the velocity of a particle starting with an initial speed of 24 m/s and decelerating at -2 m/s^2 after 8 seconds. This problem involves kinematic equations for linear motion, specifically calculating final velocity using initial velocity, acceleration, and time. Suitable for students in Grades 9-12.

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