Math Problem Statement

On a highway, a wreck occurred and caused a traffic jam 8 miles long on one side of the road. The average car is 13.5 feet in length and the average truck is 20 feet in length. 75% of the traffic jam consists of cars and 25% of trucks. If the average distance between vehicles is 3 feet, how many vehicles are stuck in the traffic jam?

Solution

To solve this problem, we need to calculate the total number of vehicles (cars and trucks) stuck in the traffic jam. Here's the step-by-step solution:

Step 1: Convert the Length of the Traffic Jam to Feet

The total length of the traffic jam is given as 8 miles. Since there are 5280 feet in a mile:

Length of traffic jam in feet=8×5280=42,240 feet\text{Length of traffic jam in feet} = 8 \times 5280 = 42,240 \text{ feet}

Step 2: Calculate the Average Length of a Car and a Truck with the Distance Between Vehicles

Let's compute the total average space taken by each car and each truck, including the 3-foot gap between vehicles:

  • The average length of a car including the gap is: Length of a car including gap=13.5+3=16.5 feet\text{Length of a car including gap} = 13.5 + 3 = 16.5 \text{ feet}

  • The average length of a truck including the gap is: Length of a truck including gap=20+3=23 feet\text{Length of a truck including gap} = 20 + 3 = 23 \text{ feet}

Step 3: Use the Percentages to Express the Total Length Covered by Cars and Trucks

Since 75% of the vehicles are cars and 25% are trucks, let’s denote:

  • xx = number of cars
  • yy = number of trucks

We can express the total length of the traffic jam in terms of the cars and trucks:

16.5x+23y=42,24016.5x + 23y = 42,240

We also know that 75% of the vehicles are cars and 25% are trucks, so:

x=0.75(x+y),y=0.25(x+y)x = 0.75(x + y), \quad y = 0.25(x + y)

Step 4: Solve for the Number of Vehicles

From the equation x=0.75(x+y)x = 0.75(x + y), we can solve for yy:

y=x3y = \frac{x}{3}

Substitute this into the total length equation:

16.5x+23(x3)=42,24016.5x + 23 \left(\frac{x}{3}\right) = 42,240

Now, simplify and solve for xx:

16.5x+23x3=42,24016.5x + \frac{23x}{3} = 42,240

Multiply everything by 3 to eliminate the fraction:

3×16.5x+23x=126,7203 \times 16.5x + 23x = 126,720

49.5x+23x=126,72049.5x + 23x = 126,720

72.5x=126,72072.5x = 126,720

x=126,72072.51,748x = \frac{126,720}{72.5} \approx 1,748

Now, find yy:

y=x3=1,7483582.67y = \frac{x}{3} = \frac{1,748}{3} \approx 582.67

Since the number of trucks must be a whole number, round to the nearest whole number:

y583y \approx 583

Step 5: Calculate the Total Number of Vehicles

Total number of vehicles NN is:

N=x+y=1,748+583=2,331N = x + y = 1,748 + 583 = 2,331

Conclusion

There are approximately 2,331 vehicles stuck in the traffic jam.

Would you like more details or have any questions about this solution?

Related Questions:

  1. What would happen to the total number of vehicles if the distance between vehicles increased to 5 feet?
  2. How would the calculation change if the percentage of cars and trucks were reversed?
  3. What is the total length in feet occupied only by the trucks?
  4. How many trucks would there be if the average truck length increased by 10%?
  5. What if the traffic jam was 12 miles long instead of 8 miles?

Tip: Remember to always include the average gap distance when calculating total lengths in traffic problems!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Percentage Calculations
Unit Conversion

Formulas

Length of traffic jam (feet) = miles * 5280
Length of vehicle with gap = vehicle length + distance between vehicles
Total length equation: 16.5x + 23y = 42,240
Vehicle percentage equation: x = 0.75(x + y), y = 0.25(x + y)

Theorems

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Suitable Grade Level

Grades 9-12