Math Problem Statement

A train travels 10 km for 50 seconds and then stops for 20 seconds. It then travels another 10 km for 75 seconds. What is the train's average velocity during all 145 seconds?

Solution

To calculate the train's average velocity during the entire 145 seconds, we need to determine the total distance traveled and the total time taken.

Step 1: Calculate the total distance traveled

The train travels two segments:

  1. First segment: 1010 km
  2. Second segment: 1010 km

So, the total distance traveled by the train is: Total distance=10km+10km=20km\text{Total distance} = 10 \, \text{km} + 10 \, \text{km} = 20 \, \text{km}

Step 2: Calculate the total time taken

The total time includes both the time the train is moving and the time it is stopped:

  1. Time moving in the first segment: 5050 seconds
  2. Stopping time: 2020 seconds
  3. Time moving in the second segment: 7575 seconds

Thus, the total time is: Total time=50seconds+20seconds+75seconds=145seconds\text{Total time} = 50 \, \text{seconds} + 20 \, \text{seconds} + 75 \, \text{seconds} = 145 \, \text{seconds}

Step 3: Calculate the average velocity

Average velocity is given by the total distance traveled divided by the total time taken: Average velocity=Total distanceTotal time=20km145seconds\text{Average velocity} = \frac{\text{Total distance}}{\text{Total time}} = \frac{20 \, \text{km}}{145 \, \text{seconds}}

Step 4: Convert to kilometers per hour (optional)

To express the average velocity in km/h: Average velocity=20km145seconds×3600seconds1hour\text{Average velocity} = \frac{20 \, \text{km}}{145 \, \text{seconds}} \times \frac{3600 \, \text{seconds}}{1 \, \text{hour}} Average velocity=20×3600145km/h496.55km/h\text{Average velocity} = \frac{20 \times 3600}{145} \, \text{km/h} \approx 496.55 \, \text{km/h}

So, the average velocity of the train during the 145 seconds is approximately 496.55 km/h.

Would you like more details or have any questions?

Related Questions:

  1. How would the average velocity change if the stopping time was doubled?
  2. What would the average speed be if the train only traveled the first segment?
  3. How does the average velocity differ from average speed in this scenario?
  4. What is the significance of the train stopping in terms of velocity calculation?
  5. How would you calculate the average velocity if the train traveled different distances at different speeds?

Tip: Remember, average velocity depends on the total displacement and total time, not just the time when the object is moving.

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Math Problem Analysis

Mathematical Concepts

Physics
Kinematics

Formulas

Average velocity formula: v_avg = total distance / total time

Theorems

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Suitable Grade Level

Grades 9-12