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The problem asks for the total thickness of a countertop, which consists of two parts:

1. The countertop itself has a thickness of 4.380 cm.
2. It is covered by a laminated plastic with a thickness of 0.158 cm.

To find the total thickness, you need to add these two values together:

\[
\text{Total thickness} = 4.380 \, \text{cm} + 0.158 \, \text{cm} = 4.538 \, \text{cm}
\]

So, the total thickness of the countertop is **4.538 cm**.

Would you like more details or have further questions?

Here are 5 related questions to explore this topic:
1. What is the process of converting thickness from centimeters to millimeters?
2. How would the calculation change if the laminate thickness was given in millimeters instead of centimeters?
3. Can we calculate the total volume of the countertop if the area was also provided?
4. How does the precision of decimal points affect measurement in construction?
5. What would happen to the total thickness if multiple layers of laminate were added?

**Tip:** When adding or subtracting measurements, always ensure the units are consistent throughout the calculation.

Un dessus de comptoir est 4.380 cm d'épaisseur et est recouvert d'un plastique laminé de 0.158 cm d'épaisseur. Quelle est l'épaisseur totale du dessus de comptoir?

Find the total thickness of a countertop covered with a laminated plastic. The countertop has a thickness of 4.380 cm, and the plastic is 0.158 cm thick. Learn how to calculate total thickness using decimal addition. Suitable for Grades 6-8.

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