An architect designed a building with one-sixth of the floors underground, and five-sixths of the floors above ground.

If there are 20 floors above ground, how many total floors does the building have?

Let's denote the total number of floors in the building as \( T \).

According to the problem, one-sixth of the floors are underground, and five-sixths of the floors are above ground. 

Given that the number of floors above ground is 20, we can set up the following equation:

\[
\frac{5}{6}T = 20
\]

To find the total number of floors \( T \), solve the equation:

\[
T = \frac{20 \times 6}{5} = \frac{120}{5} = 24
\]

So, the building has a total of **24 floors**.

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. If two floors were added underground, how many total floors would there be?
2. What percentage of the total floors are above ground?
3. If the number of underground floors doubled, how many would there be?
4. If one additional floor is built above ground, how does that affect the total number of floors?
5. How many more floors are above ground compared to underground?

**Tip:** When solving problems with fractions, it's often helpful to set up an equation and solve step by step to avoid confusion.

Learn how to calculate the total number of floors in a building with specified fractions of floors underground and above ground. This problem involves fractions and basic equations, suitable for Grades 6-8 students.

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