The question in the image is in Bengali and translates as follows:

Question: "A wheel has a moment of inertia of $10 \, \text{kg} \cdot \text{m}^2$. How much torque is needed to produce an angular acceleration of $10 \, \text{rads}^{-2}$?"

We are given:

• Moment of inertia, $I = 10 \, \text{kg} \cdot \text{m}^2$
• Angular acceleration, $\alpha = 10 \, \text{rads}^{-2}$

Using the formula for torque: $\tau = I \cdot \alpha$

Substituting the values: $\tau = 10 \, \text{kg} \cdot \text{m}^2 \times 10 \, \text{rads}^{-2} = 100 \, \text{Nm}$

Thus, the required torque is $\boxed{100 \, \text{Nm}}$, which corresponds to option D.

Would you like more details or have any other questions?

Here are 5 related questions for further practice:

1. What is the relationship between torque and angular acceleration?
2. How does moment of inertia affect the rotational motion of a body?
3. What are the SI units of moment of inertia and angular acceleration?
4. How does the distribution of mass affect the moment of inertia of a rotating object?
5. If the angular acceleration was halved, what would be the required torque?

Tip: Moment of inertia depends not just on the mass but also on how that mass is distributed relative to the axis of rotation.