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Let's solve this problem using the simple interest formula.

### Problem Recap:
- **Principal (P)**: £1140
- **Rate of interest (R)**: 0.5% per year
- **Interest earned (I)**: £285.20
- **Time (T)**: \( \text{?} \) years

### Simple Interest Formula:
The formula for simple interest is given by:
\[
I = P \times R \times T
\]
Where:
- \( I \) is the interest,
- \( P \) is the principal amount,
- \( R \) is the rate of interest per year (expressed as a decimal),
- \( T \) is the time the money is invested or borrowed for, in years.

### Convert the Rate of Interest:
The rate is given as 0.5%, which we convert to a decimal:
\[
R = \frac{0.5}{100} = 0.005
\]

### Rearrange the Formula to Solve for Time \( T \):
\[
T = \frac{I}{P \times R}
\]

### Substitute the Given Values:
\[
T = \frac{285.20}{1140 \times 0.005}
\]

Let's calculate this.The money has been in the account for approximately **50 years**.

Would you like more details or have any questions? 

Here are some related questions you might find interesting:
1. How would the time change if the interest rate was 1% instead of 0.5%?
2. What would the interest be after 60 years at the same rate?
3. How much interest would have been earned if the principal was £2000?
4. How does simple interest differ from compound interest?
5. What would happen if the interest was compounded annually instead?

**Tip:** Always double-check your decimal conversions, as small mistakes can lead to large errors in calculations.

Emily puts £1140 into a bank account which pays simple interest at a rate of 0.5% per year. After a certain number of years, the account has paid a total of £285.20 in interest. How many years has the money been in the account for?

Learn how to calculate the number of years money has been in a bank account using simple interest. In this problem, Emily invests £1140 at an interest rate of 0.5%, leading to a total interest of £285.20. Suitable for Grades 9-11 students.

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