Math Problem Statement
It takes your garden hose 17 seconds to fill your 2-gallon watering can. How long will it take to fill
a. An inflatable pool measuring 3 feet wide, 10 feet long, and 1 foot deep.
b. A circular inflatable pool 13 feet in diameter and 1 feet deep.
[Hint: 1 cubic foot = 7.48 gallons]
Solution
To solve these problems, we need to determine the volume of each pool in cubic feet, convert it to gallons, and then use the rate of water flow from the hose to figure out how long it will take to fill each pool.
Step 1: Calculate the rate of water flow
You know that it takes 17 seconds to fill a 2-gallon watering can, so we can calculate the rate of water flow in gallons per second:
Step 2: Part a - Rectangular pool
The dimensions of the rectangular pool are 3 feet wide, 10 feet long, and 1 foot deep. The volume of the pool in cubic feet is given by:
Now, convert this volume into gallons using the given conversion factor (1 cubic foot = 7.48 gallons):
Step 3: Time to fill the rectangular pool
Using the flow rate (0.118 gallons per second), the time required to fill the pool is:
Convert this into minutes:
Step 4: Part b - Circular pool
The diameter of the circular pool is 13 feet, and the depth is 1 foot. The volume of a circular pool is given by the formula for the volume of a cylinder:
Where:
- is the radius (half of the diameter, so feet),
- is the depth (1 foot).
Substitute the values:
Convert this volume into gallons:
Step 5: Time to fill the circular pool
Using the same flow rate (0.118 gallons per second), the time to fill the pool is:
Convert this into minutes:
Final Answers:
a. It will take approximately 31.7 minutes to fill the rectangular pool.
b. It will take approximately 140.2 minutes to fill the circular pool.
Would you like more details or have any questions?
Follow-up questions:
- What is the rate in gallons per minute for the hose?
- How would the time change if the diameter of the circular pool increased to 15 feet?
- How long would it take to fill half of the rectangular pool?
- What would happen if the hose flow rate decreased to 1 gallon per 17 seconds?
- How would the time change if the rectangular pool was only 0.5 feet deep?
Tip: For circular objects, always remember to use the formula for the volume of a cylinder when calculating the amount of water they hold.
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Math Problem Analysis
Mathematical Concepts
Volume Calculation
Unit Conversion
Rate Calculation
Formulas
Flow rate = gallons/seconds
Volume of a rectangular pool = width × length × depth
Volume of a circular pool = πr²h
1 cubic foot = 7.48 gallons
Time = Volume / Flow rate
Theorems
Cylindrical volume calculation
Suitable Grade Level
Grades 8-10
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