Math Problem Statement

Calculate the temperature at which each of the following reactions becomes spontaneous. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) This reaction is blank at blank K.

Solution

To calculate the temperature at which a reaction becomes spontaneous, we use the Gibbs free energy equation:

ΔG=ΔHTΔS\Delta G = \Delta H - T \Delta S

A reaction is spontaneous when ΔG<0\Delta G < 0. At the temperature where the reaction becomes spontaneous, ΔG=0\Delta G = 0, so:

0=ΔHTΔS0 = \Delta H - T \Delta S

This simplifies to:

T=ΔHΔST = \frac{\Delta H}{\Delta S}

Where:

  • ΔH\Delta H is the enthalpy change of the reaction.
  • ΔS\Delta S is the entropy change of the reaction.
  • TT is the temperature (in Kelvin).

Steps:

  1. Find ΔH\Delta H and ΔS\Delta S for the reaction PCl5(g)PCl3(g)+Cl2(g)\text{PCl}_5(g) \rightarrow \text{PCl}_3(g) + \text{Cl}_2(g).
  2. Use the equation T=ΔHΔST = \frac{\Delta H}{\Delta S}.

Could you provide the values for ΔH\Delta H and ΔS\Delta S, or would you like me to look them up?


Would you like details or have any questions on this process?
Here are 5 related questions to explore further:

  1. What is the difference between endothermic and exothermic reactions?
  2. How does entropy affect the spontaneity of a reaction?
  3. Why does ΔG\Delta G need to be negative for a reaction to be spontaneous?
  4. What other factors can influence the spontaneity of a chemical reaction?
  5. How do you calculate ΔG\Delta G at non-standard conditions?

Tip: For reactions that involve gases, remember that increasing temperature generally increases the entropy (ΔS\Delta S) of the system.

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Math Problem Analysis

Mathematical Concepts

Thermodynamics
Gibbs Free Energy
Spontaneity of Reactions

Formulas

ΔG = ΔH - TΔS
T = ΔH / ΔS

Theorems

Gibbs Free Energy Theorem
Second Law of Thermodynamics

Suitable Grade Level

College Level (Chemistry/Thermodynamics)