The outside temperature at 4 PM was 8°C the temperature decreased 3.5 Celsius each hour until 10 PM. What was the temperature at 10 PM?

To find the temperature at 10 PM, we calculate the decrease in temperature over time. The temperature decreases by 3.5°C each hour from 4 PM to 10 PM.

There are \(10\, \text{PM} - 4\, \text{PM} = 6\) hours in this period.

The total decrease in temperature is:

\[
6 \times 3.5^\circ C = 21^\circ C
\]

Now, subtract the total decrease from the initial temperature:

\[
8^\circ C - 21^\circ C = -13^\circ C
\]

Thus, the temperature at 10 PM was \(-13^\circ C\).

Would you like more details or have any questions?

Here are some related questions to expand on this:
1. How would the answer change if the temperature decreased by 2°C per hour instead?
2. What if the temperature decreased at a variable rate over the 6 hours?
3. How could we represent this situation as a linear equation?
4. What is the significance of negative temperatures in Celsius?
5. How does this compare to temperature changes in Fahrenheit?

**Tip:** Always note the rate of change

Find the temperature at 10 PM when the temperature starts at 8°C at 4 PM and decreases by 3.5°C each hour. Learn how to apply a linear relationship and rate of change to solve this real-world problem. Suitable for students in Grades 6-8.

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