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It looks like Cassie is working on building a hollow model of a pyramid, with a square base of 25 cm on each side and a slant height of 30 cm. The net shown represents the cardboard needed to construct this pyramid.

To find the total surface area of the cardboard required, we’ll need to calculate:

1. **The area of the square base:**  
   The base area is simply the side length squared:  
   \[
   25 \text{ cm} \times 25 \text{ cm} = 625 \text{ cm}^2
   \]

2. **The area of the four triangular faces:**  
   Each triangular face has a base of 25 cm and a height (slant height) of 30 cm. The area of one triangle is:
   \[
   \frac{1}{2} \times 25 \text{ cm} \times 30 \text{ cm} = 375 \text{ cm}^2
   \]
   Since there are four triangles, their combined area is:
   \[
   4 \times 375 \text{ cm}^2 = 1500 \text{ cm}^2
   \]

3. **Total surface area:**  
   Adding the area of the base and the four triangular faces:
   \[
   625 \text{ cm}^2 + 1500 \text{ cm}^2 = 2125 \text{ cm}^2
   \]

So, the total surface area of the cardboard required to make this pyramid is **2125 cm²**.

Would you like a more detailed breakdown or have any further questions?

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Here are some related questions to explore:

1. What is the volume of a pyramid with a square base?
2. How would the surface area change if the slant height was different?
3. If the base was rectangular instead of square, how would the surface area formula change?
4. How do you calculate the surface area of a cone, which has a similar shape?
5. Can you find the height of the pyramid using the slant height and the base length?

**Tip:** For any three-dimensional shape, always separate the base and side areas to calculate surface area accurately.

After reading a book about ancient Egypt, Cassie decided to build a hollow model of a pyramid out of cardboard. The base of the pyramid is a square with a side length of 25 cm, and each triangular face has a slant height of 30 cm. The net of the pyramid is shown.

Learn how to calculate the surface area of a hollow pyramid model with a square base of 25 cm per side and triangular faces with a slant height of 30 cm. This problem involves geometry concepts and area formulas, suitable for students in Grades 6-8.

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