To determine how much wrapping paper Josue used, we need to find the total surface area of the cube-shaped gift box. The net of a cube consists of six square faces, so we can calculate the surface area by finding the area of one square face and then multiplying by 6 (since there are 6 faces on a cube).

Steps to calculate the surface area:

1. Find the area of one face:
   From the problem, it appears that each side of the square is 5.3 cm. The area $A$ of a square is calculated as: $A = \text{side}^2$ So, $A = 5.3^2 = 28.09 \, \text{cm}^2$

2. Calculate the total surface area:
   Since the cube has 6 faces, the total surface area $S$ is: $S = 6 \times A = 6 \times 28.09 = 168.54 \, \text{cm}^2$

Therefore, the total amount of wrapping paper Josue used is 168.54 square centimeters.

Let me know if you need more details or have any other questions!

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Here are some related questions that might be of interest:

1. How would the surface area change if the side length of the cube was doubled?
2. If Josue had a rectangular box instead of a cube, how would we calculate its surface area?
3. How do we calculate the surface area of a cylinder compared to a cube?
4. What happens to the volume of the cube if the side length is halved?
5. What is the formula to find the surface area of any polyhedron?

Tip: To find the surface area of a cube, always remember the formula $S = 6 \times (\text{side length})^2$.