Math Problem Statement

Find the standard​ deviation, s, of sample data summarized in the frequency distribution table given below by using the formula​ below, where x represents the class​ midpoint, f represents the class​ frequency, and n represents the total number of sample values.​ Also, compare the computed standard deviation to the standard deviation obtained from the original list of data​ values, 9.09.0. sequals=StartRoot StartFraction n left bracket Summation from nothing to nothing left parenthesis f times x squared right parenthesis right bracket minus left bracket Summation from nothing to nothing left parenthesis f times x right parenthesis right bracket squared Over n left parenthesis n minus 1 right parenthesis EndFraction EndRoot n∑f•x2−∑(f•x)2 n(n−1) Interval 2020​-2929 3030​-3939 4040​-4949 5050​-5959 6060​-6969 7070​-7979

Frequency 11 1515 3939 2323 77 11

Solution

To find the standard deviation, ss, of the sample data summarized in the frequency distribution table, we need to use the given formula:

s=n((fx2))((fx))2n(n1)s = \sqrt{\frac{n \left( \sum (f \cdot x^2) \right) - \left( \sum (f \cdot x) \right)^2}{n(n-1)}}

where:

  • xx is the class midpoint,
  • ff is the class frequency,
  • nn is the total number of sample values.

Step-by-step Solution

  1. Find the Midpoints for Each Class Interval:

    The midpoint (xx) of each class interval is calculated as:

    x=lower class limit+upper class limit2x = \frac{\text{lower class limit} + \text{upper class limit}}{2}

    For each interval:

    • 2029:x=20+292=24.520-29: x = \frac{20 + 29}{2} = 24.5
    • 3039:x=30+392=34.530-39: x = \frac{30 + 39}{2} = 34.5
    • 4049:x=40+492=44.540-49: x = \frac{40 + 49}{2} = 44.5
    • 5059:x=50+592=54.550-59: x = \frac{50 + 59}{2} = 54.5
    • 6069:x=60+692=64.560-69: x = \frac{60 + 69}{2} = 64.5
    • 7079:x=70+792=74.570-79: x = \frac{70 + 79}{2} = 74.5
  2. Calculate fxf \cdot x, fx2f \cdot x^2, and Summations:

    We need to compute fxf \cdot x, fx2f \cdot x^2, and their summations.

  3. Apply the Formula to Compute the Standard Deviation:

    Finally, use the formula for the standard deviation to find ss.

Let's compute these values step-by-step.The calculated standard deviation of the sample data summarized in the frequency distribution table is approximately 11.19.

Comparison with Given Standard Deviation

  • The computed standard deviation is 11.19, whereas the given standard deviation is 9.0.
  • There is a noticeable difference between the two values, indicating that either the original data or the approximation in the grouped frequency distribution affects the result.

Would you like further details or have any questions?

Relative Questions:

  1. How does the method of calculating standard deviation change if the data is not grouped?
  2. What impact does grouping data have on the accuracy of the standard deviation?
  3. How can we calculate the mean from a frequency distribution table?
  4. What are the differences between sample standard deviation and population standard deviation?
  5. How can the standard deviation be interpreted in the context of data dispersion?

Tip: When working with grouped data, remember that the standard deviation is an approximation and may differ from the actual standard deviation of the raw data.

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Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Standard Deviation

Formulas

s = sqrt((n * Σ(f * x²) - (Σ(f * x))²) / (n(n - 1)))

Theorems

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Suitable Grade Level

Grades 11-12