One whale sang to communicate with another whale. For 3.2seconds, the song's sound wave traveled directly toward the second whale at a constant velocity. In that time, the sound wave traveled 4,800meters. What was its velocity?


To calculate the velocity of the sound wave, we can use the formula for velocity:

\[
\text{Velocity} = \frac{\text{Distance}}{\text{Time}}
\]

Given:
- Distance = 4,800 meters
- Time = 3.2 seconds

Now, calculate the velocity:

\[
\text{Velocity} = \frac{4800}{3.2} = 1500 \, \text{meters per second}
\]

So, the velocity of the sound wave is **1,500 meters per second**.

Would you like more details, or do you have any questions?

Here are 5 related questions to further explore:
1. What factors affect the speed of sound in water?
2. How does the speed of sound in water compare to its speed in air?
3. How does temperature impact the speed of sound in different mediums?
4. Can whales use echolocation, and how does it work?
5. What other animals rely on sound waves for communication in water?

**Tip:** The speed of sound varies depending on the medium—it's much faster in water than in air due to the density of the molecules!

One whale sang to communicate with another whale. For 3.2 seconds, the song's sound wave traveled directly toward the second whale at a constant velocity. In that time, the sound wave traveled 4,800 meters. What was its velocity?

Learn how to calculate the velocity of a sound wave traveling between two whales. This example covers key physics concepts such as velocity, distance, and time. In this problem, the sound wave travels 4,800 meters in 3.2 seconds, resulting in a velocity of 1,500 meters per second. Suitable for students in Grades 6-8.

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