Hey, I have doubt in slope of Line. In a question given two points (3,2) and (-1,-5) and I have to calculate slope of line. The formula is m = y2-y1/x2-x1. As question mentioned (3,2) first so I take it as (X1,Y1) and (-1,-5) as (X2,Y2). It's right way or i need to take according to graph , left to right?

When calculating the slope of a line given two points, the order in which you assign the points to \((x_1, y_1)\) and \((x_2, y_2)\) does not matter. The formula for the slope, \( m = \frac{y_2 - y_1}{x_2 - x_1} \), will yield the same result regardless of which point you assign as \((x_1, y_1)\) and which as \((x_2, y_2)\). 

Let's calculate the slope using both orders to see this in action:

1. **Assign (3, 2) as \((x_1, y_1)\) and (-1, -5) as \((x_2, y_2)\):**
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-5 - 2}{-1 - 3} = \frac{-7}{-4} = \frac{7}{4}
   \]

2. **Assign (-1, -5) as \((x_1, y_1)\) and (3, 2) as \((x_2, y_2)\):**
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - (-5)}{3 - (-1)} = \frac{2 + 5}{3 + 1} = \frac{7}{4}
   \]

As you can see, the slope \( m \) remains \( \frac{7}{4} \) regardless of the order. Therefore, you can confidently use any point as \((x_1, y_1)\) and the other as \((x_2, y_2)\) without worrying about the order.

Would you like more details on this topic or have any other questions? Here are some related questions you might find interesting:

1. How do you interpret the slope of a line in real-world scenarios?
2. How does the slope relate to the angle of the line with the horizontal axis?
3. Can you calculate the slope if one of the points is the origin?
4. How do you find the equation of a line given two points?
5. What happens to the slope when the line is vertical or horizontal?

**Tip:** Always double-check your calculations by reordering the points to ensure consistency in your results.

Learn how to calculate the slope of a line using the slope formula with two given points (3, 2) and (-1, -5). Understand the method to find slope irrespective of point order. Suitable for Grades 7-9.

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