Math Problem Statement
resuelve
Solution
The problem asks to calculate the shaded area in the image provided. The figure consists of a quarter circle with center and radius , and a square inscribed within the quarter circle.
Let's break down the solution:
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Radius of the quarter circle: The quarter circle's radius is equal to the distance or .
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Side of the square: Let's denote the side of the square as . Since the square is inscribed, one of its vertices lies on the circle, and the square touches the circle at two other points.
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Relationship between the square and circle: The diagonal of the square is the same as the radius of the quarter circle. The diagonal can be related to the side of the square using the Pythagorean theorem: But since , we have: Solving for :
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Area of the quarter circle: The area of the quarter circle is:
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Area of the square: The area of the square is:
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Shaded area: The shaded area is the difference between the area of the quarter circle and the area of the square: Simplifying further:
So, the shaded area is .
Would you like further details on any of these steps, or do you have any questions?
Related Questions:
- How would the shaded area change if the figure was a semicircle instead of a quarter circle?
- What would the relationship be if the square was not inscribed but circumscribed around the quarter circle?
- Can you derive the area of the square in terms of the circumference of the full circle?
- What happens to the shaded area if the square is scaled down or up?
- How would you calculate the shaded area if the square was rotated within the quarter circle?
Tip:
When dealing with geometry problems involving circles and polygons, it’s often useful to explore relationships between the radius, side lengths, and angles using trigonometry or the Pythagorean theorem.
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Math Problem Analysis
Mathematical Concepts
Geometry
Circle
Square
Area Calculation
Formulas
Area of quarter circle: (1/4) * π * r^2
Area of square inscribed in a circle: s^2 = (r / sqrt(2))^2
Theorems
Pythagorean theorem
Suitable Grade Level
High School
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