There are 10 lanes in the bowling alley where Harold bowls. The lanes are side-by-side with no gaps. He wants to make a scale drawing of the bowling alley using a scale of 3 cm to 15 ft. One lane, including gutters, is 60 ft long and 5 ft wide. What will the width of the 10 lanes on his drawing will be?

To find the width of the 10 lanes in Harold's scale drawing, we'll need to use the given scale and the dimensions of the lanes.

### Step 1: Determine the actual width of the 10 lanes.
Each lane is 5 feet wide. Since there are 10 lanes:

\[
\text{Total width of 10 lanes} = 10 \times 5 \text{ ft} = 50 \text{ ft}
\]

### Step 2: Apply the scale to the total width.
The scale given is 3 cm to 15 ft. This means:

\[
\text{Scale factor} = \frac{3 \text{ cm}}{15 \text{ ft}} = \frac{1 \text{ cm}}{5 \text{ ft}}
\]

Now, use the scale factor to convert the total width of 50 feet into centimeters:

\[
\text{Width in the drawing} = \frac{1 \text{ cm}}{5 \text{ ft}} \times 50 \text{ ft} = 10 \text{ cm}
\]

### Final Answer:
The width of the 10 lanes on Harold's drawing will be **10 cm**.

Would you like more details or have any other questions? Here are some related questions you might find interesting:

1. What will be the length of each lane in Harold's drawing?
2. How would the dimensions change if the scale was 2 cm to 15 ft?
3. How much area does the 10 lanes occupy on the actual bowling alley?
4. What would be the total area of the lanes on the drawing?
5. How would you calculate the perimeter of one lane on the drawing?

**Tip:** Always double-check the scale to ensure accurate conversions when working on scale drawings.

Learn how to calculate the width of 10 bowling lanes in a scale drawing using a scale of 3 cm to 15 ft. This problem involves scale drawings, unit conversion, and applying scale factors. Suitable for middle school students (Grades 6-8).

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