The problem asks to calculate the resonance frequency for a series LCR circuit, where the given values are:

• $L = 60 \, \text{mH} = 60 \times 10^{-3} \, \text{H}$
• $C = 450 \, \text{pF} = 450 \times 10^{-12} \, \text{F}$
• $R = 1000 \, \Omega$

For a series LCR circuit, the resonance frequency $f_0$ is given by the formula:

$f_0 = \frac{1}{2\pi \sqrt{LC}}$

Now, let me calculate the resonance frequency.The resonance frequency of the series LCR circuit is approximately $30,629 \, \text{Hz}$ or $30.63 \, \text{kHz}$.

Would you like further details or have any questions? Here are 5 related questions for practice:

1. What happens to the resonance frequency if the capacitance is doubled?
2. How does the resistance $R$ affect the bandwidth of the resonance?
3. What is the significance of resonance frequency in an LCR circuit?
4. How can we experimentally determine the resonance frequency in a real circuit?
5. How does changing the inductance affect the resonance frequency?

Tip: At resonance, the impedance of the LCR circuit is purely resistive, meaning the reactive components from the inductor and capacitor cancel each other out.