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The problem asks to calculate the resonance frequency for a series LCR circuit, where the given values are:

- \( L = 60 \, \text{mH} = 60 \times 10^{-3} \, \text{H} \)
- \( C = 450 \, \text{pF} = 450 \times 10^{-12} \, \text{F} \)
- \( R = 1000 \, \Omega \)

For a series LCR circuit, the resonance frequency \( f_0 \) is given by the formula:

\[
f_0 = \frac{1}{2\pi \sqrt{LC}}
\]

Now, let me calculate the resonance frequency.The resonance frequency of the series LCR circuit is approximately \( 30,629 \, \text{Hz} \) or \( 30.63 \, \text{kHz} \).

Would you like further details or have any questions? Here are 5 related questions for practice:

1. What happens to the resonance frequency if the capacitance is doubled?
2. How does the resistance \(R\) affect the bandwidth of the resonance?
3. What is the significance of resonance frequency in an LCR circuit?
4. How can we experimentally determine the resonance frequency in a real circuit?
5. How does changing the inductance affect the resonance frequency?

**Tip:** At resonance, the impedance of the LCR circuit is purely resistive, meaning the reactive components from the inductor and capacitor cancel each other out.

In the series LCR circuit, if L = 60 mH, C = 450 pF and R = 1000 Ω, calculate the resonance frequency?

Learn how to calculate the resonance frequency for a series LCR circuit given L = 60 mH, C = 450 pF, and R = 1000 Ω. Understand key formulas and concepts related to resonance in electrical circuits.

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