Math Problem Statement

A wire of length 1 m has a resistance of 2 Ω. What is the resistance of the second wire whose specific resistance is double that of the first, if the length of the wire is 3 m and the diameter is double that of the first?

Solution

Problem Analysis

We are tasked with finding the resistance of a second wire given the following conditions:

  1. The first wire has a resistance R1=2ΩR_1 = 2 \, \Omega, a length L1=1mL_1 = 1 \, \text{m}, and a specific resistivity ρ\rho.
  2. The second wire has:
    • Length: L2=3mL_2 = 3 \, \text{m},
    • Diameter: Twice that of the first wire (d2=2d1d_2 = 2d_1),
    • Specific resistance (resistivity): ρ2=2ρ1\rho_2 = 2\rho_1 (double the resistivity of the first wire).

The resistance RR of a wire is determined using the formula: R=ρLAR = \rho \frac{L}{A} where:

  • ρ\rho is the resistivity,
  • LL is the length,
  • AA is the cross-sectional area (A=πr2A = \pi r^2, where rr is the radius).

Step-by-Step Solution

  1. First Wire's Characteristics: For the first wire: R1=ρ1L1A1R_1 = \rho_1 \frac{L_1}{A_1} Substituting L1=1mL_1 = 1 \, \text{m}, A1=πr12A_1 = \pi r_1^2: R1=ρ11πr12R_1 = \rho_1 \frac{1}{\pi r_1^2} Given R1=2ΩR_1 = 2 \, \Omega: ρ1=2πr12\rho_1 = 2 \pi r_1^2

  2. Second Wire's Characteristics: For the second wire:

    • Resistivity ρ2=2ρ1\rho_2 = 2\rho_1,
    • Length L2=3mL_2 = 3 \, \text{m},
    • Radius r2=2r1r_2 = 2r_1, so cross-sectional area A2=πr22=π(2r1)2=4πr12A_2 = \pi r_2^2 = \pi (2r_1)^2 = 4\pi r_1^2.

    Substituting these into the resistance formula: R2=ρ2L2A2R_2 = \rho_2 \frac{L_2}{A_2} Substitute ρ2=2ρ1\rho_2 = 2\rho_1, L2=3L_2 = 3, A2=4πr12A_2 = 4\pi r_1^2: R2=(2ρ1)34πr12R_2 = (2\rho_1) \frac{3}{4\pi r_1^2} Substitute ρ1=2πr12\rho_1 = 2 \pi r_1^2 from the first wire: R2=2(2πr12)34πr12R_2 = 2(2\pi r_1^2) \frac{3}{4\pi r_1^2} Simplify: R2=3ΩR_2 = 3 \, \Omega

Final Answer:

The resistance of the second wire is: 3Ω\boxed{3 \, \Omega}


Would you like a more detailed explanation of any specific step or assistance with related problems? Here are 5 related questions to explore:

  1. How does the resistivity affect the resistance of a wire?
  2. What happens to resistance if only the length of the wire changes?
  3. How is resistance affected if both diameter and resistivity change inversely?
  4. What role does temperature play in the resistivity of a material?
  5. Can the resistance formula be experimentally verified? How?

Tip: Always consider the dependency of resistance on both geometric and material properties while solving wire-related problems.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Electrical Resistance
Geometry
Specific Resistance

Formulas

R = ρ * L / A
A = π * r^2

Theorems

Direct Proportionality between Resistance and Length
Inverse Proportionality between Resistance and Area

Suitable Grade Level

Grades 9-12