Math Problem Statement
Solution
Problem Analysis
We are tasked with finding the resistance of a second wire given the following conditions:
- The first wire has a resistance , a length , and a specific resistivity .
- The second wire has:
- Length: ,
- Diameter: Twice that of the first wire (),
- Specific resistance (resistivity): (double the resistivity of the first wire).
The resistance of a wire is determined using the formula: where:
- is the resistivity,
- is the length,
- is the cross-sectional area (, where is the radius).
Step-by-Step Solution
-
First Wire's Characteristics: For the first wire: Substituting , : Given :
-
Second Wire's Characteristics: For the second wire:
- Resistivity ,
- Length ,
- Radius , so cross-sectional area .
Substituting these into the resistance formula: Substitute , , : Substitute from the first wire: Simplify:
Final Answer:
The resistance of the second wire is:
Would you like a more detailed explanation of any specific step or assistance with related problems? Here are 5 related questions to explore:
- How does the resistivity affect the resistance of a wire?
- What happens to resistance if only the length of the wire changes?
- How is resistance affected if both diameter and resistivity change inversely?
- What role does temperature play in the resistivity of a material?
- Can the resistance formula be experimentally verified? How?
Tip: Always consider the dependency of resistance on both geometric and material properties while solving wire-related problems.
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Math Problem Analysis
Mathematical Concepts
Electrical Resistance
Geometry
Specific Resistance
Formulas
R = ρ * L / A
A = π * r^2
Theorems
Direct Proportionality between Resistance and Length
Inverse Proportionality between Resistance and Area
Suitable Grade Level
Grades 9-12
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