Given the scenario:

• The gas tank holds 60 litres of fuel.
• It is currently a quarter full, so it has $\frac{1}{4} \times 60 = 15$ litres of fuel.
• You burn $\frac{1}{2}$ litre per hour driven.

Let's define:

• $t$ as the number of hours driven.
• $f(t)$ as the fuel remaining in the tank after $t$ hours.

The fuel consumed after $t$ hours is $\frac{1}{2} \times t$ litres.

The formula for the fuel remaining in the tank after $t$ hours is:

$f(t) = 15 - \frac{1}{2}t$

This formula represents the amount of fuel left in the tank as a function of the number of hours driven.

Would you like a more detailed explanation or have any other questions?

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Here are 5 related questions for further practice:

1. If the tank was half full instead of a quarter, what would the formula for the fuel remaining be?
2. How long can you drive before the tank is empty?
3. How much fuel would remain after 10 hours of driving?
4. If the fuel consumption increased to $\frac{3}{4}$ litres per hour, how would the formula change?
5. What would the graph of the function $f(t)$ look like?

Tip: When working with word problems, identify all given information and variables before setting up the equation.