Math Problem Statement
A swimming pool is being drained at a constant rate of 15 gallons per minute. The pool initially holds 1,200 gallons of water.
Which equation represents the amount of water, g , left in the pool after t minutes? A.t=−15g+1,200
B.g=15t−1,200
C.g=−15t+1,200
D.t=15g+1,200
Solution
The problem describes a situation where a swimming pool is being drained at a constant rate of 15 gallons per minute. Initially, the pool holds 1,200 gallons of water. To find the equation that represents the amount of water, , left in the pool after minutes, we can set up a linear relationship.
- The pool starts with 1,200 gallons, and every minute, 15 gallons are drained.
- Therefore, the amount of water in the pool decreases by 15 gallons for every minute that passes.
This gives us the equation: Rearranging it, we see that it matches the form of option C:
Correct Answer: C. g = -15t + 1,200
Would you like further details or have any questions?
Here are 5 related questions to deepen your understanding:
- How would the equation change if the pool was being filled at 15 gallons per minute instead of drained?
- What would the equation be if the initial volume of the pool was different, say 2,000 gallons?
- How much water would be left in the pool after 30 minutes of draining?
- How long will it take for the pool to completely empty?
- What would happen to the slope of the equation if the draining rate increased to 20 gallons per minute?
Tip: The slope in a linear equation often represents the rate of change in problems involving time and quantity, such as draining or filling.
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
Rates of Change
Formulas
g = −15t + 1,200
Theorems
Slope-Intercept Form of a Linear Equation
Suitable Grade Level
Grades 6-8