Math Problem Statement

Find the probability of the event P(A ∪ B) if P(A) = 0.17, P(B) = 0.34, and P(A ∩ B) = 0.14.

Solution

To calculate P(AB)P(A \cup B), we use the formula:

P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)

Given:

  • P(A)=0.17P(A) = 0.17
  • P(B)=0.34P(B) = 0.34
  • P(AB)=0.14P(A \cap B) = 0.14

Substitute the values:

P(AB)=0.17+0.340.14P(A \cup B) = 0.17 + 0.34 - 0.14

P(AB)=0.37P(A \cup B) = 0.37

Thus, P(AB)=0.37P(A \cup B) = 0.37.

Would you like a detailed breakdown or have further questions? Here are 5 related questions for exploration:

  1. What does P(AB)P(A \cap B) represent in probability terms?
  2. How would P(AB)P(A \cup B) change if P(AB)=0P(A \cap B) = 0?
  3. How can this formula be extended for more than two events?
  4. What are examples of mutually exclusive events in real-life applications?
  5. How does this formula relate to the inclusion-exclusion principle in set theory?

Tip: Always check whether events are mutually exclusive when calculating probabilities, as P(AB)P(A \cap B) would equal 0

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Math Problem Analysis

Mathematical Concepts

Probability
Set Operations
Union and Intersection

Formulas

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 9-12