The question 3(1) from the image reads:

**3(1)**: "If \( P(A) = 0.5 \), \( P(B) = 0.6 \), and \( P(A \cap B) = 0.2 \), find \( P(A \cup B) \)."

To solve this, we will use the formula for the union of two events in probability:

\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]

### Given:
- \( P(A) = 0.5 \)
- \( P(B) = 0.6 \)
- \( P(A \cap B) = 0.2 \)

### Plugging in the values:
\[
P(A \cup B) = 0.5 + 0.6 - 0.2
\]

\[
P(A \cup B) = 1.1 - 0.2 = 0.9
\]

### Final Answer:
The probability \( P(A \cup B) \) is \( 0.9 \).

Would you like to ask more questions or need further details on this topic? Here are some related questions you might consider:

1. What is the meaning of \( P(A \cap B) \) in probability theory?
2. How do we interpret \( P(A \cup B) \) in practical scenarios?
3. Can the value of \( P(A \cup B) \) ever exceed 1? Why or why not?
4. How do we find \( P(A^c) \), the complement of event \( A \)?
5. What does it mean if two events \( A \) and \( B \) are mutually exclusive?

**Tip:** When calculating probabilities involving unions and intersections, always consider the overlap (intersection) between the events to avoid overestimating the total probability.

Learn how to calculate the probability of the union of events A and B with given probabilities. This problem involves basic probability concepts, including the union formula and intersection. Suitable for high school students.

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