The question asks for the probability that a student chosen at random did not get a "C." Here's how to solve it:

Step 1: Total number of students

From the table: $\text{Total students} = 75$

Step 2: Students who got a "C"

The total number of students who got a "C" is: $\text{Students who got a "C"} = 27$

Step 3: Students who did not get a "C"

$\text{Students who did not get a "C"} = \text{Total students} - \text{Students who got a "C"} = 75 - 27 = 48$

Step 4: Probability

The probability of choosing a student who did not get a "C" is: $P(\text{Not C}) = \frac{\text{Students who did not get a "C"}}{\text{Total students}} = \frac{48}{75}$

Simplify the fraction: $P(\text{Not C}) = \frac{16}{25} \quad \text{or approximately } 0.64 \, (64\%)$

Final Answer:

$P(\text{Not C}) = \frac{16}{25} \, \text{or } 64\%.$

Would you like further clarification or additional examples?

5 Related Questions:

1. What is the probability of selecting a male who got an "A"?
2. What is the probability of selecting a female student?
3. What is the probability of selecting a student who got a "B"?
4. What is the probability of selecting a student who got an "A" or "B"?
5. How would the probabilities change if 10 more students were added to the total?

Tip:

Always double-check totals when calculating probabilities to ensure no errors in summation or categorization!