Math Problem Statement

for any 2 events , P(A) = 0.55 , P(0.35) , P(AU B) = 0.75 , find P(A' U B)

Solution

To find P(AB)P(A' \cup B), we can use the complementary rule and set theory properties.

Given:

  1. P(A)=0.55P(A) = 0.55
  2. P(B)=0.35P(B) = 0.35
  3. P(AB)=0.75P(A \cup B) = 0.75

Solution:

Step 1: Complement Rule

The event ABA' \cup B (the complement of AA union BB) can be expressed as:

P(AB)=1P(AB).P(A' \cup B) = 1 - P(A \cap B').

Step 2: Decompose P(AB)P(A \cup B)

Using the formula for the union of two events:

P(AB)=P(A)+P(B)P(AB).P(A \cup B) = P(A) + P(B) - P(A \cap B).

Substitute the given values:

0.75=0.55+0.35P(AB).0.75 = 0.55 + 0.35 - P(A \cap B).

Solve for P(AB)P(A \cap B):

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Math Problem Analysis

Mathematical Concepts

Probability
Set Theory
Complement Rule

Formulas

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
P(A' ∪ B) = 1 - P(A ∩ B')

Theorems

Probability Complement Rule
Inclusion-Exclusion Principle

Suitable Grade Level

Grades 10-12