To calculate the probability that Penelope will select either an apple or lime chew, we first need to compute the relative frequencies based on the results of the experiment.

1. Total number of trials = 33.
2. Number of times an apple chew was selected = 9.
3. Number of times a lime chew was selected = 11.

The total number of favorable outcomes (either apple or lime chews) is:

$9 \, (\text{apple chews}) + 11 \, (\text{lime chews}) = 20$

The probability of selecting either an apple or a lime chew is:

$P(\text{apple or lime}) = \frac{20}{33}$

Now, convert this probability to a percentage:

$P(\text{apple or lime}) = \frac{20}{33} \times 100 \approx 60.61\%$

Rounding to the nearest whole number, the probability is:

$\boxed{61\%}$

Would you like further details on the calculations or have any questions?

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Here are 5 related questions:

1. How would the probability change if Penelope selected 5 more orange chews?
2. What is the probability of selecting an orange chew based on the experiment results?
3. If Penelope performed the experiment 100 times, how would you predict the new frequency for apple chews?
4. What is the probability that Penelope selects exactly 2 lime chews in 5 trials?
5. How would the probability change if the number of lime chews was halved?

Tip: Probabilities always sum to 100% for mutually exclusive outcomes.