determine the pressure in psi, 60 ft below the surface of the sea (given the SG of water is 1.022 and the barometer reading is 29.2 in Hg)

To determine the pressure 60 feet below the sea surface, we need to consider both the atmospheric pressure and the pressure due to the water column above the point in question. Here's the step-by-step process:

### 1. **Convert Atmospheric Pressure to psi**
   - The barometer reading is given as \( 29.2 \) inches of mercury (in Hg).
   - \( 1 \) inch of mercury \( = 0.4912 \) psi.
   - Atmospheric pressure (\( P_{\text{atm}} \)) in psi:
   \[
   P_{\text{atm}} = 29.2 \, \text{in Hg} \times 0.4912 \, \text{psi/in Hg} = 14.34 \, \text{psi}
   \]

### 2. **Calculate the Pressure Due to the Water Column**
   - The specific gravity (SG) of seawater is \( 1.022 \).
   - The density of pure water is approximately \( 62.4 \, \text{lb/ft}^3 \).
   - Density of seawater (\( \rho_{\text{seawater}} \)) is:
   \[
   \rho_{\text{seawater}} = 1.022 \times 62.4 \, \text{lb/ft}^3 = 63.765 \, \text{lb/ft}^3
   \]
   - The depth (\( h \)) is \( 60 \) feet.
   - The pressure due to the water column (\( P_{\text{water}} \)) is given by:
   \[
   P_{\text{water}} = \rho_{\text{seawater}} \times g \times h
   \]
   Where \( g \) is the acceleration due to gravity, but in these units:
   \[
   P_{\text{water}} = 63.765 \, \text{lb/ft}^3 \times 60 \, \text{ft} = 3825.9 \, \text{lb/ft}^2
   \]
   - Convert \( \text{lb/ft}^2 \) to psi (\( 1 \, \text{psi} = 144 \, \text{lb/ft}^2 \)):
   \[
   P_{\text{water}} = \frac{3825.9}{144} = 26.57 \, \text{psi}
   \]

### 3. **Total Pressure at 60 ft Depth**
   - Total pressure (\( P_{\text{total}} \)) is the sum of atmospheric pressure and water pressure:
   \[
   P_{\text{total}} = P_{\text{atm}} + P_{\text{water}} = 14.34 \, \text{psi} + 26.57 \, \text{psi} = 40.91 \, \text{psi}
   \]

So, the pressure 60 feet below the surface of the sea is approximately **40.91 psi**.

Would you like a more detailed explanation or have any questions?

### Related Questions:
1. How does the specific gravity of seawater affect the pressure at a given depth?
2. What would the pressure be at 100 feet below the surface with the same conditions?
3. How would the pressure change if the barometer reading was different?
4. How does this calculation change for freshwater instead of seawater?
5. What is the importance of considering atmospheric pressure in underwater pressure calculations?

### Tip:
Always ensure you convert all units to a consistent system (e.g., all pressures to psi) before performing calculations for clarity and accuracy.

Determine the pressure in psi, 60 ft below the surface of the sea (given the SG of water is 1.022 and the barometer reading is 29.2 in Hg).

Find out how to calculate the pressure at 60 feet below the sea surface with a specific gravity of seawater of 1.022 and a barometer reading of 29.2 in Hg. This detailed solution covers fluid mechanics, pressure calculations, and unit conversions, suitable for college-level students.

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