Increase 7000 by 8% then decrease the result by 10%. Find the overall percentage change of the original 7000.

Let's break down the problem step by step.

1. **Increase 7000 by 8%:**
   \[
   7000 \times 1.08 = 7560
   \]

2. **Decrease the result by 10%:**
   \[
   7560 \times 0.90 = 6804
   \]

3. **Find the overall percentage change:**

   The original amount was 7000, and the final amount is 6804.

   The percentage change is calculated as:
   \[
   \text{Percentage Change} = \frac{\text{Final Amount} - \text{Original Amount}}{\text{Original Amount}} \times 100
   \]
   \[
   \text{Percentage Change} = \frac{6804 - 7000}{7000} \times 100 = \frac{-196}{7000} \times 100 \approx -2.8\%
   \]

So, the overall percentage change is approximately **-2.8%**.

Do you want more details or have any questions? 

Here are some related questions:
1. What would be the final amount if you increased 7000 by 12% instead of 8% and then decreased by 10%?
2. How does the order of operations (increasing first or decreasing first) affect the final result?
3. What is the net percentage change if you increase a number by 15% and then decrease it by 15%?
4. Can you achieve a net positive change by first decreasing by 10% and then increasing by 10%?
5. What is the overall percentage change if you increase a value by 20% and then decrease by 25%?
6. How do you calculate the percentage change if multiple increases and decreases are applied in sequence?
7. How does compounding affect percentage change calculations?
8. What is the final amount after increasing 7000 by 8%, then decreasing by 10%, and then increasing by 5%?

**Tip:** When applying multiple percentage changes, the order of operations matters. Always calculate each step sequentially.

Learn how to calculate percentage change when increasing 7000 by 8% and then decreasing the result by 10%. This problem involves basic arithmetic operations with percentages and is suitable for Grades 6-8 students.

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