Math Problem Statement

solve this with each step with explanation

Solution

To find the coefficient of correlation for the given data, we can use Pearson's correlation coefficient formula. Let's go through each step in detail.

Given Data

The data given in the table is:

XY
1018
1412
1824
226
2630
3036

Pearson's Correlation Coefficient Formula

The Pearson correlation coefficient rr is calculated using the formula:

[ r = \frac{n(\sum XY) - (\sum X)(\sum Y)}{\sqrt{[n\sum X^2 - (\sum X)^2][n\sum Y^2 - (\sum Y)^2]}} ]

Where:

  • nn is the number of data points.
  • XY\sum XY is the sum of the product of each pair of XX and YY.
  • X\sum X and Y\sum Y are the sums of XX and YY values respectively.
  • X2\sum X^2 and Y2\sum Y^2 are the sums of the squares of XX and YY values respectively.

Let's calculate each part step by step.

Step 1: Calculate the Sums

  1. Calculate X\sum X and Y\sum Y:

    X=10+14+18+22+26+30=120\sum X = 10 + 14 + 18 + 22 + 26 + 30 = 120

    Y=18+12+24+6+30+36=126\sum Y = 18 + 12 + 24 + 6 + 30 + 36 = 126

  2. Calculate XY\sum XY:

    XY=(10×18)+(14×12)+(18×24)+(22×6)+(26×30)+(30×36)\sum XY = (10 \times 18) + (14 \times 12) + (18 \times 24) + (22 \times 6) + (26 \times 30) + (30 \times 36)

    =180+168+432+132+780+1080=2772= 180 + 168 + 432 + 132 + 780 + 1080 = 2772

  3. Calculate X2\sum X^2 and Y2\sum Y^2:

    X2=102+142+182+222+262+302\sum X^2 = 10^2 + 14^2 + 18^2 + 22^2 + 26^2 + 30^2

    =100+196+324+484+676+900=2680= 100 + 196 + 324 + 484 + 676 + 900 = 2680

    Y2=182+122+242+62+302+362\sum Y^2 = 18^2 + 12^2 + 24^2 + 6^2 + 30^2 + 36^2

    =324+144+576+36+900+1296=3276= 324 + 144 + 576 + 36 + 900 + 1296 = 3276

Step 2: Calculate the Correlation Coefficient

Substitute the calculated sums into the Pearson correlation formula:

r=6×2772120×126(6×26801202)(6×32761262)r = \frac{6 \times 2772 - 120 \times 126}{\sqrt{(6 \times 2680 - 120^2)(6 \times 3276 - 126^2)}}

r=1663215120(1608014400)(1965615876)r = \frac{16632 - 15120}{\sqrt{(16080 - 14400)(19656 - 15876)}}

r=15121680×3780r = \frac{1512}{\sqrt{1680 \times 3780}}

r=15126350400r = \frac{1512}{\sqrt{6350400}}

r=15122520r = \frac{1512}{2520}

r0.6r \approx 0.6

Conclusion

The Pearson correlation coefficient r0.6r \approx 0.6 indicates a moderate positive correlation between XX and YY.


Would you like any further explanation or details on any step? Here are some additional questions you might have:

  1. What does the correlation coefficient tell us about the relationship between XX and YY?
  2. How can we interpret the result in terms of statistical significance?
  3. What are the limitations of using Pearson's correlation coefficient?
  4. How would the correlation change if we add more data points?
  5. Can you explain how to calculate a correlation coefficient using a different method?

Tip: When analyzing correlations, always visualize your data with a scatter plot to see if the linear correlation is a suitable model.

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation

Formulas

Pearson's correlation coefficient

Theorems

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Suitable Grade Level

Undergraduate Level