parking charges of a car in New Delhi Railway station for the first two hours are ₹50 and ₹10 for subsequent hours. Write egh for the total Charge for six hours.

Let's break down the problem for calculating the total parking charge for six hours:

1. The first two hours cost ₹50.
2. For each subsequent hour after the first two, it costs ₹10 per hour.
   
For six hours:
- The first 2 hours cost ₹50.
- There are \( 6 - 2 = 4 \) subsequent hours, and each of these costs ₹10.

Thus, the total charge is calculated as:
\[
\text{Total charge} = 50 + (4 \times 10) = 50 + 40 = 90
\]

Therefore, the total parking charge for six hours is ₹90.

Would you like further details or have any questions?

Here are 5 related questions for expansion:
1. What would the total charge be for 10 hours?
2. How would the charges change if the rate for subsequent hours were ₹15 instead of ₹10?
3. Can you express the total parking charge as a mathematical function for \(n\) hours?
4. If the rate for the first two hours increased to ₹70, how would it affect the total for six hours?
5. How much would the charge be for a full 24-hour period?

**Tip:** Whenever you encounter a parking charge question, break the problem into fixed charges (like the first two hours) and variable charges (for subsequent hours).

Parking charges of a car in New Delhi Railway station for the first two hours are ₹50 and ₹10 for subsequent hours. Write egh for the total charge for six hours.

Learn how to calculate the total parking charges for a car at New Delhi Railway station. The first two hours cost ₹50, and the rate is ₹10 for each subsequent hour. This example solves for a 6-hour parking period and provides step-by-step calculations for students in Grades 4-6.

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