To solve this problem, we need to calculate the area of the ceiling and then determine how many pints of paint are needed based on the coverage of one pint of paint.

Step 1: Calculate the area of the ceiling.

The dimensions of the room are given in inches: 90 inches by 111 inches. To find the area in square feet, we must first convert these dimensions to feet:

• $90 \, \text{inches} = \frac{90}{12} = 7.5 \, \text{feet}$
• $111 \, \text{inches} = \frac{111}{12} = 9.25 \, \text{feet}$

Now, calculate the area: $\text{Area} = 7.5 \times 9.25 = 69.375 \, \text{square feet}$

Step 2: Determine how many pints of paint are needed.

We know that 1 pint of paint covers 50 square feet. So, to find how many pints are required, divide the ceiling area by the coverage of one pint: $\frac{69.375 \, \text{square feet}}{50 \, \text{square feet per pint}} = 1.3875 \, \text{pints}$

Since we cannot buy a fraction of a pint, round up to the nearest whole pint: $\text{Pints needed} = 2$

Final Answer:

You would need 2 pints of paint to cover the ceiling.

Let me know if you'd like more details or if you have further questions.

Related Questions:

1. How would the number of pints change if the dimensions were doubled?
2. What if the coverage per pint were 40 square feet instead of 50?
3. How many pints would be needed to paint both the ceiling and the walls?
4. How much paint would be needed for a room with dimensions 100 inches by 120 inches?
5. What if the paint coverage was given in square meters instead of square feet?

Tip:

Always round up when calculating how many units of paint or tiles to purchase, since partial quantities are not usually sold.