Math Problem Statement
30, 31, 32, 33, 34, 35, 35, 37, 39, 40, 44, 46, 49, 49, 49, 51, 53, 56, 58, 58, 59, 59, 61, 62, 63, 64, 64, 64, 65, 66, 70, 70, 71, 72, 72, 76, 81, 82, 82, 86. The Q1 is 42 and the Q3 is 68. The median is 58.5. (c) Find the upper and lower outlier boundaries.
Solution
To find the upper and lower outlier boundaries, we can use the interquartile range (IQR) method. The formula for determining these boundaries is:
Step 1: Calculate the IQR
The interquartile range (IQR) is the difference between the third quartile (Q3) and the first quartile (Q1).
Step 2: Find the lower boundary
Step 3: Find the upper boundary
Final Boundaries
- Lower boundary: 3
- Upper boundary: 107
Any data points outside this range (below 3 or above 107) would be considered outliers.
Would you like further details or have any questions?
Here are 5 related questions for deeper understanding:
- How do we calculate quartiles from a data set?
- What is the significance of the interquartile range (IQR)?
- How do outliers affect data analysis?
- What are some other methods to detect outliers besides the IQR method?
- Why is 1.5 used as a multiplier when calculating outlier boundaries?
Tip: Quartiles divide data into four equal parts, and understanding them helps in assessing the spread and distribution of your data.
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Math Problem Analysis
Mathematical Concepts
Statistics
Outliers
Quartiles
Interquartile Range
Formulas
Lower boundary = Q1 - 1.5 × IQR
Upper boundary = Q3 + 1.5 × IQR
IQR = Q3 - Q1
Theorems
Interquartile Range Method for Detecting Outliers
Suitable Grade Level
Grades 10-12