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Let's break down the problem and solve it.

1. **Original Situation:**
   - Distance to the airport = 35 miles.
   - Usual time = 42 minutes.
   - Usual speed = \( \frac{35 \text{ miles}}{42 \text{ minutes}} \times 60 \) (since we want speed in miles per hour).

2. **New Situation:**
   - Speed is reduced by 11 miles per hour.
   - We need to find the new time it would take to travel the same 35 miles and convert that to minutes.

### Step-by-Step Solution:

First, let's calculate the usual speed:

\[
\text{Usual speed} = \frac{35}{42} \times 60 \text{ miles per hour}.
\]

Next, reduce that speed by 11 mph to get the new speed.

Then, use the formula for time:

\[
\text{New time (hours)} = \frac{35 \text{ miles}}{\text{New speed (mph)}}.
\]

Finally, convert that time into minutes and round up to the next minute.

Let me calculate that for you.The traveler should budget **54 minutes** for the trip home from the airport after the reduction in speed.

Would you like any further details or explanations? Here are five related questions to explore:

1. How do you calculate average speed for different trips?
2. What happens to the travel time if the speed decreases by a greater margin?
3. Can this method be applied to trips with varying distances?
4. What other factors could affect travel time beyond speed?
5. How does reducing speed affect fuel efficiency?

**Tip:** When speed decreases, travel time increases in an inverse proportion. This relationship is crucial in real-life planning, like road trips!

On the way to the airport, a traveler hits a huge hole in a construction area, damaging the right front wheel. The temporary tire forced her to decrease her average speed by 11 miles per hour. If the 35-mile drive usually takes 42 minutes, how much time should be budgeted for the trip home from the airport? Round up to the next minute, if needed.

Learn how to calculate the new travel time when a traveler reduces her speed by 11 mph after damaging her wheel. This detailed problem involves distance, speed, and time relationships, and provides a step-by-step solution. Suitable for Grades 7-9.

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