To determine the magnitude of the net force needed to achieve the motion shown in the velocity-time graph, we need to go through the following steps:

1. Identify the motion details:

• The graph shows velocity $v$ (in m/s) plotted against time $t$ (in seconds). The relationship between velocity and time is linear, indicating uniform acceleration.

• The slope of the line represents the acceleration $a$, as: $a = \frac{\Delta v}{\Delta t}$

  From the graph:

  • Initial velocity $v_0 = 0 \, \text{m/s}$ at $t = 0 \, \text{s}$
  • Final velocity $v_f = 0.3 \, \text{m/s}$ at $t = 0.3 \, \text{s}$

  So, acceleration $a$ is: $a = \frac{0.3 \, \text{m/s}}{0.3 \, \text{s}} = 1 \, \text{m/s}^2$

2. Use Newton's Second Law:

To calculate the force, we need the mass $m$ of the object. Newton's second law states: $F = m \cdot a$

• If the mass $m$ is known, we can compute the net force required to achieve the motion.

Conclusion:

The acceleration of the object is $1 \, \text{m/s}^2$. To find the net force, you need to know the mass $m$. If you provide the mass, I can complete the calculation.

Would you like to provide the mass, or should I assume a value for illustrative purposes?

Here are five questions related to this concept:

1. What is the significance of the slope in a velocity-time graph?
2. How does uniform acceleration differ from non-uniform acceleration?
3. What happens to the net force if the mass of the object is doubled?
4. How is Newton's second law applied to real-world problems like this?
5. Can you describe the relationship between velocity, acceleration, and force?

Tip: In physics, the area under a velocity-time graph gives the displacement of the object over that period.