Math Problem Statement
Find NA and acceptance angle of a fiber with core index 1.4 and Δ = 0.02.
Solution
To calculate the Numerical Aperture (NA) and the Acceptance Angle of the fiber, we can use the following formulas:
1. Numerical Aperture (NA):
Where:
- = Core refractive index.
- = Cladding refractive index.
The relation between and is given by the Relative Index Difference (Δ): From this, we can solve for :
2. Acceptance Angle (θₐ):
The acceptance angle (in air) is related to the Numerical Aperture: Then,
Given:
- Core refractive index
Let's compute the Numerical Aperture and the Acceptance Angle.### Results:
- Numerical Aperture (NA): 0.28
- Acceptance Angle (θₐ): 16.26°
Would you like more details or have any further questions?
Here are 5 related questions for further understanding:
- How does increasing the core index affect the Numerical Aperture?
- What is the role of the cladding in fiber optics?
- How does the relative index difference influence the fiber's performance?
- Can Numerical Aperture be greater than 1? Why or why not?
- How does the acceptance angle impact light propagation within the fiber?
Tip: A larger Numerical Aperture allows the fiber to capture light at wider angles, improving light collection efficiency.
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Math Problem Analysis
Mathematical Concepts
Numerical Aperture (NA)
Acceptance Angle
Relative Index Difference (Δ)
Optical Fiber Theory
Formulas
NA = sqrt(n1^2 - n2^2)
Δ = (n1^2 - n2^2) / (2n1^2)
n2 = n1 * sqrt(1 - 2Δ)
sin(θa) = NA
θa = arcsin(NA)
Theorems
Snell's Law
Fiber Optic Light Propagation
Suitable Grade Level
Undergraduate level (Physics/Optics)
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