A farmer ties 4 bags on his mule. The mule can carry up to 200 lb and each bag weighs 30 lb. How many more bags can the mule carry?

The mule can carry up to 200 pounds, and each bag weighs 30 pounds. Let's break down the problem:

1. The mule currently has 4 bags, so the total weight being carried is:
   \[
   4 \times 30 \text{ lb} = 120 \text{ lb}
   \]

2. The mule's carrying capacity is 200 pounds. Therefore, the remaining capacity is:
   \[
   200 \text{ lb} - 120 \text{ lb} = 80 \text{ lb}
   \]

3. Since each additional bag weighs 30 pounds, the number of more bags the mule can carry is:
   \[
   \frac{80 \text{ lb}}{30 \text{ lb per bag}} = \frac{80}{30} \approx 2.67
   \]
   Since the mule can't carry a fraction of a bag, it can carry **2 more bags**.

Would you like more details or have any other questions?

Here are 5 related questions:
1. If the weight of each bag was 50 lb, how many bags could the mule carry?
2. How many pounds of load would the mule carry if it had 7 bags?
3. If the mule carried 8 bags, how much would the total weight exceed its carrying capacity?
4. What if each bag's weight was reduced by 5 lb, how many more bags could the mule carry?
5. How much total weight can two mules carry if each can handle 200 lb?

**Tip:** When working with fractional results in real-life scenarios, it's important to consider whether fractions make practical sense, such as when counting physical items.

Learn how to calculate how many more bags a mule can carry based on its maximum capacity and the weight of each bag. This problem involves basic arithmetic and understanding weight and capacity concepts. Suitable for students in Grades 4-6.

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