A company owning a shopping centre decides to reduce the lighting load in the parking garage by installing a new lighting configuration. The old lighting configuration was a 300 kW installation while the new configuration is a 130 kW installation. Assume that the lights are operation 24 h/d and the cost of electricity is 45 c/kWh. What is the monthly saving achieved? Select one correct answer.

To calculate the monthly savings achieved by reducing the lighting load, we need to determine the difference in energy consumption between the old and new lighting configurations and then calculate the cost savings.

### Step-by-Step Solution:

1. **Calculate the power consumption per day for both configurations:**

   - **Old configuration:**  
     \[
     \text{Power} = 300 \, \text{kW}
     \]  
     \[
     \text{Energy consumption per day} = 300 \, \text{kW} \times 24 \, \text{hours} = 7200 \, \text{kWh}
     \]

   - **New configuration:**  
     \[
     \text{Power} = 130 \, \text{kW}
     \]  
     \[
     \text{Energy consumption per day} = 130 \, \text{kW} \times 24 \, \text{hours} = 3120 \, \text{kWh}
     \]

2. **Calculate the daily energy savings:**

   \[
   \text{Daily savings in energy consumption} = 7200 \, \text{kWh} - 3120 \, \text{kWh} = 4080 \, \text{kWh}
   \]

3. **Calculate the monthly energy savings:**

   Assuming a month has 30 days:
   \[
   \text{Monthly savings in energy consumption} = 4080 \, \text{k

Discover how to calculate monthly savings achieved by changing a lighting configuration from 300 kW to 130 kW. This problem involves understanding power consumption, energy calculation, and cost savings based on electricity rates. Ideal for high school students learning practical applications of energy efficiency calculations.

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