Math Problem Statement
A company's charge for electricity is 8.230¢ per kilowatt-hour. In addition, each monthly bill contains a customer charge of $6.37. If last year's bills ranged from a low of $55.97 to a high of $201.64, over what range did usage vary (in kilowatt-hours)?
Solution
We are given the following:
- The electricity rate is 8.230¢ per kilowatt-hour (kWh), which is dollars per kWh.
- There is a fixed monthly customer charge of dollars.
- The bills range from a low of dollars to a high of dollars.
We need to find the range of usage in kilowatt-hours (kWh).
Step 1: Setup the formula for the monthly bill
The total bill is the sum of the fixed customer charge and the charge based on the number of kilowatt-hours used:
Step 2: Find usage at the low end of the bill range
For the low bill , we can use the equation:
Solve for (kilowatt-hours used):
Step 3: Find usage at the high end of the bill range
For the high bill , we use the same equation: Solve for :
Step 4: Conclusion
The usage ranged from approximately to .
Do you want more details or have any other questions?
Here are 5 relative questions for you:
- How do varying rates affect overall electricity consumption?
- What are the advantages of a fixed customer charge?
- How can you estimate your average electricity usage based on your bill?
- How does the cost of electricity compare between different seasons?
- How would the bill change if the rate per kilowatt-hour increased?
Tip: Tracking your monthly energy consumption can help identify patterns that can reduce your overall bill.
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Math Problem Analysis
Mathematical Concepts
Linear Equations
Unit Rates
Basic Algebra
Formulas
B = 6.37 + 0.08230x
x = (B - 6.37) / 0.08230
Theorems
-
Suitable Grade Level
Grades 8-10
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