Math Problem Statement

Obtain mode of the following distribution. Classes 10-20,20-30 ,30 40 ,40-50, 50-60 ,60-70 Frequency 8 ,2 ,25 ,45 ,11 ,9

Solution

To find the mode of a frequency distribution, we use the class with the highest frequency as the modal class. Let's go through the steps to determine the mode for the given dataTo find the mode of a frequency distribution, we use the class with the highest frequency as the modal class. Let's go through the steps to determine the mode for the given

Step 1: Identify the modal class

The class intervals and their corresponding frequencies are:

  • 102010-20: Frequency = 8
  • 203020-30: Frequency = 2
  • 304030-40: Frequency = 25
  • 405040-50: Frequency = 45
  • 506050-60: Frequency = 11
  • 607060-70: Frequency = 9

The modal class is the class with the highest frequency. Here, the highest frequency is 45, which corresponds to the class interval 40-50.

Step 2: Use the mode formula

The formula to calculate the mode for a grouped frequency distribution is: Mode=L+(fmf1(fmf1)+(fmf2))×h\text{Mode} = L + \left( \frac{f_m - f_1}{(f_m - f_1) + (f_m - f_2)} \right) \times h where:

  • LL = Lower boundary of the modal class
  • fmf_m = Frequency of the modal class
  • f1f_1 = Frequency of the class before the modal class
  • f2f_2 = Frequency of the class after the modal class
  • hh = Class width

From the dataTo find the mode of a frequency distribution, we use the class with the highest frequency as the modal class. Let's go through the steps to determine the mode for the given

Step 1: Identify the modal class

The class intervals and their corresponding frequencies are:

  • 102010-20: Frequency = 8
  • 203020-30: Frequency = 2
  • 304030-40: Frequency = 25
  • 405040-50: Frequency = 45
  • 506050-60: Frequency = 11
  • 607060-70: Frequency = 9

The modal class is the class with the highest frequency. Here, the highest frequency is 45, which corresponds to the class interval 40-50.

Step 2: Use the mode formula

The formula to calculate the mode for a grouped frequency distribution is: Mode=L+(fmf1(fmf1)+(fmf2))×h\text{Mode} = L + \left( \frac{f_m - f_1}{(f_m - f_1) + (f_m - f_2)} \right) \times h where:

  • LL = Lower boundary of the modal class
  • fmf_m = Frequency of the modal class
  • f1f_1 = Frequency of the class before the modal class
  • f2f_2 = Frequency of the class after the modal class
  • hh = Class width

From the

  • L=40L = 40 (lower boundary of the modal class)
  • fm=45f_m = 45 (frequency of the modal class)
  • f1=25f_1 = 25 (frequency of the class before the modal class)
  • f2=11f_2 = 11 (frequency of the class after the modal class)
  • h=10h = 10 (class width)

Step 3: Apply the values to the formula

Mode=40+(4525(4525)+(4511))×10\text{Mode} = 40 + \left( \frac{45 - 25}{(45 - 25) + (45 - 11)} \right) \times 10 =40+(2020+34)×10= 40 + \left( \frac{20}{20 + 34} \right) \times 10 =40+(2054)×10= 40 + \left( \frac{20}{54} \right) \times 10 =40+(0.3704)×10= 40 + \left( 0.3704 \right) \times 10 =40+3.704= 40 + 3.704 43.70\approx 43.70

Conclusion

The mode of the given distribution is approximately 43.70.

Would you like further details on the calculation, or have any questions?

Here are some related questions you might find helpful:

  1. What is the median of the same distribution?
  2. How do you calculate the mean for grouped data?
  3. Can we determine skewness from the mode and mean?
  4. What are other methods to estimate the mode?
  5. How does the mode change if we alter the frequency values?

Tip: In frequency distributions, the mode is often a useful measure for understanding the most common value or range of values in a dataset.

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Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Mode

Formulas

Mode = L + ( (fm - f1) / ( (fm - f1) + (fm - f2) ) ) * h

Theorems

None specifically applicable

Suitable Grade Level

Grades 9-12