The formula for the area of a trapezium is:

$A = \frac{1}{2} \cdot (a + b) \cdot h$

Where:

• $A$ is the area of the trapezium,
• $a$ and $b$ are the lengths of the parallel sides,
• $h$ is the height.

Rearranging the formula to solve for $b$:

$b = \frac{2A}{h} - a$

Now substitute the given values:

• $A = 111.6$,
• $a = 26.2$,
• $h = 6.2$.

$b = \frac{2 \cdot 111.6}{6.2} - 26.2$

First, calculate:

$\frac{2 \cdot 111.6}{6.2} = \frac{223.2}{6.2} \approx 36.0$

Then subtract $a$:

$b = 36.0 - 26.2 = 9.8$

Final Answer:

The length of the other parallel side is:

$b = 9.8$

Would you like further details or assistance with a similar problem?

Related Questions:

1. How is the formula for the area of a trapezium derived geometrically?
2. What happens to the area if both parallel sides are increased proportionally?
3. How can you solve for height if both parallel sides and the area are known?
4. What are the units for area, if the sides and height are given in meters?
5. How does changing the height affect the area while keeping the parallel sides constant?

Tip:

Always ensure the units of all given dimensions match when applying geometric formulas.