The national gender pay gap in the education and training industry is 11.3% If women in this industry earn $69061.20 per year, what would be the average yearly earnings be for men?

To find the average yearly earnings for men in the education and training industry given a gender pay gap of 11.3% and women's earnings of $69,061.20, we can use the formula for the pay gap:

\[
\text{Pay Gap} = \frac{\text{Men's Earnings} - \text{Women's Earnings}}{\text{Men's Earnings}}
\]

Given that the pay gap is 11.3% (or 0.113 in decimal form), we can rearrange the formula to solve for men's earnings:

\[
0.113 = \frac{\text{Men's Earnings} - 69,061.20}{\text{Men's Earnings}}
\]

Let $ x $ represent men's earnings. Now, solve for $ x $:

\[
0.113 = \frac{x - 69,061.20}{x}
\]

Multiply both sides by $ x $:

\[
0.113x = x - 69,061.20
\]

Now, subtract $ 0.113x $ from both sides:

\[
0 = x - 0.113x - 69,061.20
\]

This simplifies to:

\[
0.887x = 69,061.20
\]

Now, solve for $ x $:

\[
x = \frac{69,061.20}{0.887} = 77,860.20
\]

So, the average yearly earnings for men in the education and training industry would be **$77,860.20**.

Would you like more details or have any questions about this? 

Here are 5 related questions:
1. How is the gender pay gap calculated in other industries?
2. What other factors might contribute to pay disparities besides gender?
3. How does the gender pay gap vary across different professions in education?
4. What steps are being taken to address the gender pay gap?
5. How does the gender pay gap in education compare to the national average?

**Tip:** Always double-check whether the pay gap is being calculated as a percentage of men's or women's earnings—this can affect how you set up your equations!

The national gender pay gap in the education and training industry is 11.3%. If women in this industry earn $69,061.20 per year, what would be the average yearly earnings for men?

Find the average yearly earnings for men in the education industry using a gender pay gap of 11.3% and women's annual earnings of $69,061.20. This problem involves key algebraic concepts and percentage calculations, suitable for Grades 9-12 students.

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